4x^2-25=x

Solution for 4x^2-25=x equation:

4x^2-25=x

We move all terms to the left:

4x^2-25-(x)=0

We add all the numbers together, and all the variables

4x^2-1x-25=0

a = 4; b = -1; c = -25;
Δ = b2-4ac
Δ = -12-4·4·(-25)
Δ = 401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{401}}{2*4}=\frac{1-\sqrt{401}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{401}}{2*4}=\frac{1+\sqrt{401}}{8}
$